In an obtuse-angled triangle (ABC), the square on the side (AB) subtending the obtuse angle exceeds the sum of squares on the sides (BC, CA) containing the obtuse angle, by twice the rectangle contained by either of them (BC), and its continuation (CD) to meet a perpendicular (AD) on it from the opposite angle.
In an obtuse-angled triangle (ABC), the square on the side (AB) subtending the obtuse angle exceeds the sum of squares on the sides (BC, CA) containing the obtuse angle, by twice the rectangle contained by either of them (BC), and its continuation (CD) to meet a perpendicular (AD) on it from the opposite angle.